1=4x^2y^4

Solution for 1=4x^2y^4 equation:

Simplifying
1 = 4x2y4

Solving
1 = 4x2y4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x2y4' to each side of the equation.
1 + -4x2y4 = 4x2y4 + -4x2y4

Combine like terms: 4x2y4 + -4x2y4 = 0
1 + -4x2y4 = 0

Add '-1' to each side of the equation.
1 + -1 + -4x2y4 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4x2y4 = 0 + -1
-4x2y4 = 0 + -1

Combine like terms: 0 + -1 = -1
-4x2y4 = -1

Divide each side by '-4y4'.
x2 = 0.25y-4

Simplifying
x2 = 0.25y-4

Take the square root of each side:
x = {-0.5y-2, 0.5y-2}